Answer:
0.6708 or 67.08%
Step-by-step explanation:
Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:
There is a 0.6708 probability that Helen makes both free throws.
Answer:
I don't now this but you should do pemdas that really helped me
Step-by-step explanation:
The first step is perthansies then exponents and then multiplication then division and last addition and subtraction that should give you your answer.
Answer:
∠ 1,3,5,7 = 32°
∠2,4,6,8,= 148°
Step-by-step explanation:
From the figure attached,
AB and CD are two parallel lines and another transverse line is intersecting these line at two distinct points.
Since, m∠1 = 32°,
∠1 and ∠4 are supplementary angles [Linear pair of angles]
m∠1 + m∠4 = 180°
32° + m∠4 = 180°
m∠4 = 180° - 32°
m∠4 = 148°
therefore,
m∠1,3,5,7 = 32°
m∠2,4,6,8,= 148°
Answer:
They purchased 14 adult tickets and 4 kids tickets.
Step-by-step explanation:
14 x 5 = 70
3x4=12
and then add 70 plus 12 to get 82 dollars.
For both Carnivals to have the same cost, 10 tickets will have to be purchased.
Carnival M :
Entrance fee = $5.00
Cost per ticket = $0.50
Carnival P :
Entrance fee = $7.00
Cost per ticket = $0.30
Let the Number of ticket = n
Cost of n Carnival M tickets :
5 + 0.50n - - - (1)
Cost of n Carnival P tickets :
7 + 0.30n - - - (2)
Value of n in other to have the same price :
(1) = (2)
5 + 0.50n = 7 + 0.30n
Collect like terms
0.50n - 0.30n = 7 - 5
0.20n = 2
Divide both sides by 0.20
n = 2 / 0.20
n = 10
Therefore, 10 tickets has to be purchased for both Carnivals to have the same cost.
Learn more : brainly.com/question/18796573
