Answer:
12.875
Explanation:
Balanced equation of the reaction:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
mole of acid = mole of base
75 × 0.150 = volume of base needed × 0.3
volume of base needed = 37.5 ml
excess OH = 0.3 × 37.5 ml / 150 ml where total volume = 75 ml + 75 ml = 150 ml
excess OH = 0.075 M
pOH = - log (OH⁻) = - log (0.075 M) = 1.125
pH + pOH = 14
pH = 14 - pOH = 14 - 1.125 = 12.875
Answer:Graphite has a giant covalent structure in which: each carbon atom is joined to three other carbon atoms by covalent bonds.
The element involved in the process of petrification, replacement, and permineralization is silica, were petrification is the combination of 2 types of fossilization, replacement, and permineralization
Permineralization is a way of fossilization in which minerals ( like silica have deposited the fill the empty pores of shells or the hard animal parts). Petrification is a process where the organic material is converted to stone by replacing the original material and the pores with minerals, and Replacement occurs when the original bones or shells dissolve away and is replaced by a different mineral, which occurs along with permineralization, the whole process is called petrification.
To know more about fossilization refer to the link brainly.com/question/6867325?referrer=searchResults.
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Answer:
It is always less than the theoretical yield
Explanation:
For many chemical reactions, the actual yield is usually less than the theoretical yield. This is due to possible loss in the process or inefficiency of the chemical reaction.
Answer:
525.1 g of BaSO₄ are produced.
Explanation:
The reaction of precipitation is:
Na₂SO₄ (aq) + BaCl₂ (aq) → BaSO₄ (s) ↓ + 2NaCl (aq)
Ratio is 1:1. So 1 mol of sodium sulfate can make precipitate 1 mol of barium sulfate.
The excersise determines that the excess is the BaCl₂.
After the reaction goes complete and, at 100 % yield reaction, 2.25 moles of BaSO₄ are produced.
We convert the moles to mass: 2.25 mol . 233.38 g/mol = 525.1 g
The precipitation's equilibrium is:
SO₄⁻² (aq) + Ba²⁺ (aq) ⇄ BaSO₄ (s) ↓ Kps
