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Alborosie
3 years ago
7

The systematic names for water, ammonia, and methane are dihydrogen monoxide, H2O; trihydrogen nitride, NH3; and tetrahydrogen c

arbide, CH4. Why do most people, including chemists, prefer to use the common names for these compounds?
Chemistry
1 answer:
Papessa [141]3 years ago
6 0

Answer:

Most people, including chemists, prefer to use these common names for the compounds mentioned because they are frequently found, and the common names are shorter, easier to pronounce, and more widely known.

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Forces between similar molecules are said to be
podryga [215]

Answer:

Forces between similar molecules are said to be <em>cohesive</em> while those between different types of molecules are said to be <em>adhesive</em>.

Water 'beads' due to its strong <em>cohesive</em> forces. The meniscus of water in a glass tube is <em>concave</em> because the <em>adhesive</em> forces are strong.

Explanation:

The water in a tube has stronger adhesive forces between the water and glass molecules, so the cohesive forces between water molecules are weaker. That makes the water 'ascend' through the tube, giving a concave form of the meniscus. Another example is mercury, which is the opposite. In this case, the cohesive forces are stronger than the adhesive ones, thus the meniscus is convex.

4 0
3 years ago
Write the electron configuration for N and N-3. How many electrons are in the valence energy level?
Alinara [238K]

Non-valence electrons: 1s22s22p6. Therefore, we write the electron configuration for Na: 1s22s22p63s1. What is the highest principal quantum number that you see in sodium's electron configuration? It's n = 3, so all electrons with n = 3 are valence electrons, and all electrons with n < 3 are non-valence electrons.

8 0
3 years ago
Help me I got stuck<br> Pls
Sophie [7]
The answer is C because the weight is going down so they form a gas.
3 0
3 years ago
Calculate the mass, in grams, of Ag2CrO4 that will precipitate when 50.0mL of 0.20M AgNO3 solution is mixed with 40.0mL of 0.10M
Darina [25.2K]

Answer:

1.327 g Ag₂CrO₄

Explanation:

The reaction that takes place is:

  • 2AgNO₃(aq) + K₂CrO₄(aq)  → Ag₂CrO₄(s) + 2KNO₃(aq)

First we need to <em>identify the limiting reactant</em>:

We have:

  • 0.20 M * 50.0 mL = 10 mmol of AgNO₃
  • 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄

If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.

Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:

  • 4 mmol K₂CrO₄ * \frac{1mmolAg_2CrO_4}{1mmolK_2CrO_4} *\frac{331.73mg}{1mmolAg_2CrO_4} = 1326.92 mg Ag₂CrO₄
  • 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄
7 0
2 years ago
Lewis structure of graphite
Andreas93 [3]
Its a C with 4 dots, 1 on top,1 on bottom, 1 on the left and 1 on the right

6 0
3 years ago
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