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MatroZZZ [7]
3 years ago
7

Sodium fluoride is added to pure water and stirred to dissolve. Compared to pure water, the new solution is__________.

Chemistry
1 answer:
NeX [460]3 years ago
8 0

Answer:

Basic

Explanation:

Sodium\ Fluoride\ +\ Water = Hydrogen\ Fluoride +\ Sodium\ Hydroxide  

NaF + H_{2}O\rightarrow HF + NaOH

Sodium fluoride, NaF, is a soluble salt that dissociates completely in aqueous solution to give sodium cations, Na+, and fluoride anions, F-

NaF\rightarrow Na^{+} +F^{-}

and when it dissolve in water the pH of the solution becomes greater than seven thereby becoming basic.

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For each pair of salts, determine which of the salts, if any, would be expected to be more soluble in acidic solution than in pu
gogolik [260]

Answer:

AgNO2

Explanation:

The question asks to know which of these two insoluble salts is expected to be more soluble in acidic solution than in pure water.

To answer this question specifically, we need to know if the anions contained in the insoluble salt is a conjugate of a weak acid or that of a weak base.

Generally, the solubility of insoluble salts that contain anions which are conjugates of weak acids increases in the presence of an acidic solution than in water. While, the solubility of insoluble salts that contain anions which are conjugates of strong acids decreases in the presence of an acidic solution.

Having said this, AgNO2 contains NO2 which is the conjugate base of the Trioxonitrate iii acid which is a weak acid. Hence, it is expected to be stronger in acidic solution than in water.

4 0
3 years ago
Match the chemical reactions with their properties.
scoray [572]

Explanation:

where are the chemical reactions and their properties to match ?????????

5 0
2 years ago
A chemist is using a solution of HNO3 that has a pH of 3.75.
elena-s [515]
What you have to keep in mind is that 
pH   =  - log[H+]
so 3.75 = -log[H+], we get [H+]=10^{-3.75},
that is [H+]≈1.77827941×10^{-4}(i see this result on calculator)
this is just what you want!

5 0
3 years ago
Read 2 more answers
BRAINLIESTTTT ASAP!!! PLEASE HELP MEEEE :)
Scilla [17]

Precise is the close proximity of repeated measurements.  In order to be precise, you need two or more measurements.

Accurate is the close proximity to the real (or expected) measurement.

<u>For Example: </u>

You are at the grocery store buying watermelons.  The sign says that the watermelons all weigh 2 lbs.  You weigh 3 of them on the scale next to the watermelon display.  Their weights are 1.77, 1.80, and 1.82.  

→ The <u>scale is precise</u> because it weighs all 3 of them at nearly the same value.

→ The <u>scale is not accurate </u> because their weights are not close to the expected value of 2.0

You take one of the watermelons to the cashier.  The scale at the checkout counter weighs it as 1.99.  The scale at the checkout counter is accurate.  You cannot determine the precision of the scale at the checkout counter because you have no other values to compare it to.

Answer:  Precise CANNOT be determined by one measurement.  

               Accurate CAN be determined by one measurement.

4 0
4 years ago
Gold(ill) hydroxide is used in medicine, porcelain making, and gold plating. It is quite insoluble in aqueous solution. Which of
erik [133]

Answer:

NH3(aq)

Explanation:

Gold III hydroxide is an inorganic compound also known as auric acid. It can be dehydrated at about 140°C to yield gold III oxide. Gold III hydroxide is found to form precipitates in alkaline solutions hence it is not soluble in calcium hydroxide.

However, gold III hydroxide forms an inorganic complex with ammonia which makes the insoluble gold III hydroxide to dissolve in ammonia solution. The equation of this complex formation is shown below;

Au(OH)3(s) + 4 NH3(aq) -------> [Au(NH3)4]^3+(aq) + 3OH^-(aq)

Hence the formation of a tetra amine complex of gold III will lead to the dissolution of gold III hydroxide solid in aqueous ammonia.

6 0
4 years ago
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