Ask question

Ask question

All categories

2 years ago

12

This is the number of protons and neutrons i the nucleus of any atom

1 answer:

icang [17]2 years ago

4 0

Answer:

The mass number is defined as the total number of protons and neutrons in an atom. Consider Table below which shows data from the first six elements of the periodic table. Consider the element helium. Its atomic number is 2, so it has two protons in its nucleus.

Explanation:

You might be interested in

1. What is the potential energy of a 8 kg ball that is at a height of 20 m?

weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) = 1176 J

4 0

2 years ago

Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =

Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Wherem

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314 J / K mol

Thus, given that, $E_a$ = ?

$k_2=4.0\times 10^3s^{-1}$

$k_1=1.5\times 10^3s^{-1}$

$T_1=5\ ^0C$

$T_2=25\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (5 + 273.15) K = 278.15 K

T = (25 + 273.15) K = 298.15 K

$T_1=278.15\ K$

$T_2=298.15\ K$

So,

$\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)$

$E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}$

$E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}$

$E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}$

$E_a=33813.28\ J/mol$

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0

2 years ago

0.820 L has a mass of 2.56kg what is the density of this liquid in kg/L

3241004551 [841]

Density ρ= $\frac{m}{v}$

= $\frac{2.56 kg}{0.820 L} \\=3.121kg/L$

8 0

3 years ago

Then, in the light independent photosynthetic reactions, that energy is used to convert co2 into ________.

Svetradugi [14.3K]

In photosynthesis, light energy is used to convert CO2 into carbohydrates.

7 0

3 years ago

I need help with this question ASAP

Valentin [98]

Answer:

I think its A)

Explanation: im not sure im sorry

6 0

3 years ago