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anzhelika [568]
3 years ago
15

suppose you plan to ride your bicycle from portland oregon to seattle washington and back to portland. the distance between port

land and seattle is 175 miles. you plan to ride 25 miles each day. write the absolute value function d(x) where x is the number of days into the ride.
Mathematics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

d(x) = 175 - |175 - 25x|

Step-by-step explanation:

Suppose I plan to ride your bicycle from Portland Oregon to Seattle Washington and back to Portland.

Portland and Seattle are 175 miles apart. I plan to travel 25 miles every day.

If we consider the starting point i.e. Portland as the zero distance i.e. reference, then we can model the distance from Portland d(x) as

d(x) = 175 - |175 - 25x|

where x is the number of days into the ride. (Answer)

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7/8 and 3/4 in addition to complete the fraction box?
krok68 [10]
7/8 and 3/4 
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3 0
3 years ago
When the input is 200 what is the output? Explain please.
anygoal [31]
The slope formula is delta y/delta x=m
You can choose any two points. Let's choose (0,25) and (1,30)
30-25/1-0=5/1=5
Slope intercept form is y=mx+b
b=the y intercept
y=5x+25 since (0,25) is the coordinates for the y inthercept.
Plug in 200: y=5(200)+25
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Your welcome
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3 years ago
A receptionist named Bruce spends 2 minutes routing each incoming phone call. In all, how many phone call does Bruce have to rou
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Answer: 2 calls

Step-by-step explanation:

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2 years ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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2 years ago
A car travels 120 miles in 2.5 hours (with a constant speed). What is the car's
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