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3 years ago

6

Can any kind soul help me please

1 answer:

NeX [460]3 years ago

3 0

Answer:

Cot is an inverse of tan:

${ \tt{4 \cot( \theta) = \tan( \theta) }} \\ { \tt{ \frac{4}{ \tan( \theta) } = \tan( \theta) }} \\ \\ { \tt{4 = { \tan }^{2} \theta }} \\ { \tt{ \tan \theta = ±2}} \\ { \bf{\theta =±63.4 \degree }}$

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Compounds are different than elements because compounds are-

lutik1710 [3]

Step-by-step explanation:

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. ... Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds. They contain only one type of molecule.

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3 years ago

We will use the values off(x) at the points 0.0,0.2,0.4,0.6,0.8. Generate the data set beforeyou start the numerical integration

leva [86]

Answer:

Check attachment for complete question and answer

8 0

3 years ago

Macy is making a border out of strips of wall boarder placed end to end along the 12-foot wall in her room. Each strip is foot l

slavikrds [6]

3 for each wall so the totally is 12

4 0

3 years ago

If cos(x) = 0.5, then what is x?

Anestetic [448]

Answer:

=60 the second option.

Step-by-step explanation:

Given the trigonometric ratio, we can find the value of the angle by simply finding the inverse of the given ratio.

If for example Cos ∅= a, then ∅=Cos⁻¹a

If Cos (x)= 0.5, then x= Cos⁻¹ 0.5

Cos⁻1 0.5=60°

The angle whose sine is 0.5 is ∅=60°

5 0

3 years ago

Read 2 more answers

Y = 4x+1 y=x^2 + 2x - 2 A.6,2 B. 2,6 C. -6,2 D. -6,-2

natta225 [31]

Answer:

The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

Step-by-step explanation:

Given that

$y = 4x + 1 (i)$

$y = x^2 + 2x -2 (ii)$

Now, by susbstituting the value of 'y' from equation i to equation ii, we get

$4x+1=x^2 + 2x -2$

$0=x^2 + 2x -2-4x-1$

$0=x^2 + (2x -4x) +(-2-1)$

$0=x^2 + (-2x) +(-3)$

$0=x^2 -2x -3$

$x^2 -2x -3 = 0 (iii)$

Now by factorization, equation iii can be written as

$x^2 -3x +x -3 = 0$

$x(x -3) + 1(x -3) = 0$

$(x -3)(x +1) = 0$

x = 3 and x = -1

By putting the values of x in equation i, we get

y = 4(3) + 1

y = 12 +1

y = 13

and

y = 4(-1) + 1

y = -4 +1

y = -3

Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

7 0

3 years ago