Answer:
Step-by-step explanation:
Problem One (left panel)
<em><u>Question A</u></em>
- The y intercept happens when x = 0
- That being said, the y intercept is 50. It was moving when the timing began.
<em><u>Question B</u></em>
The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.
<em><u>Question C</u></em>
- 60 = a + (n-1)d
- 60 = 50 + (n - 1)*2
- 10/2 = (n - 1)*2/2
- 5 = n - 1
- 6 = n
The way I have done it the domain is n from 1 to 6
Question 2 (Right Panel)
<em><u>Question A</u></em>
The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.
- f(0) = ax + b
- -3 = a*0) + b
- b = - 3
- So far what you have is
- f(x) = ax - 3
- f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- - 6 = a(-1) - 3 add 3 to both sides
- -6 +3 = a(-1) -3 + 3
- -3 = a*(-1) Divide by - 1
- a = 3
- f(x) = 3x - 3 Answer for f(x)
- The slope of f(x) = the coefficient in front of the x
- f(x) has a slope of 3
- g(x) has a slope of 4
<em><u>Part B</u></em>
- f(x) has a y intercept of - 3
- g(x) has a y intercept of -5
- f(x) has the greater y intercept.
- -3 > - 5
Answer:
Adam is typing...
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu
Surface area= [15*3*2]+[20*3*2]+[10*3*2]+[14*3*2]+[15*3*2]+[14*2.5*2]
surface area=90+120+60+84+90+70=514 in²
the answer is 514 in²
