Depends of the size of the quadrilateral in relation to the circle, but otherwise, yes
Let S = spoon
Let K = knife
1 knife is thee times the cost of a spoon, so it would be 3S
Now you have 9S + 12K = 82.80
We can replace the K with 3S:
9S +12(3S) = 82.80
Simplify the left side:
9S + 36S = 82.80
Add:
45S = 82.80
Divide both sides by 45"
S = 82.80 / 45
S = 1.84
One spoon cost $1.84
We know one knife cost 3 times as much, so multiply the cost of a spoon by 3:
Knife = 1.84 x 3 = $5.52
Step-by-step explanation:
g(n-7) = (n-7) ^2-6/7 (n-7) = n^2 -14n+49-6/7 n +6= n^2-104/7 n +55
Answer:
x = 27
y = 29
Step-by-step explanation:
Answer:
The two parallel sides a and b are 17 cm and 23 cm respectively
Step-by-step explanation:
Area of a trapezium = {(a+b)/2} h
Where
h = height = 18 cm
a = parallel side 1 = x
b = parallel side 2 = x + 6
Area of a trapezium = {(a+b)/2} h
360 = {(x + x + 6) / 2} 18
360 = { (2x + 6) / 2} 18
360 = (2x + 6) 9
360 = 18x + 54
Subtract 54 from both sides
360 - 54 = 18x
306 = 18x
Divide both sides by 18
x = 306 / 18
= 17
x = 17 cm
a = parallel side 1 = x
x = 17 cm
b = parallel side 2 = x + 6
x + 6
= 17 + 6
= 23 cm
