#43 please help have mid terms Tomorrow

Mathematics

1 answer:

nirvana33 [79]3 years ago

7 0

Answer:

Job A is more profitable for nearly 49 months (or 50 months including the first month)

Job B is more profitable after 49 months (or 50 months including the first month).

Step-by-step explanation:

Let x be the number of months passed after first month

Job A:

$2,000 for the first month with a $300 raise every month thereafter

Function describing this situation:

$f(x)=2,000+300x$

Job B:

$1,500 for the first month with a 5% raise every month thereafter

Function describing this situation:

$g(x)=1,500\cdot (1+0.05)^x\\ \\g(x)=1,500\cdot 1.05^x$

Plot both graphs (see attached diagram). The diagram shows that the job A is more profitable for nearly 49 months (or 50 months including the first month) and the job B is more profitable after 49 months (or 50 months including the first month).

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If fx) is a linear function, which statement must be true?

Hitman42 [59]

Answer:

B. f(x) has no x2-term.

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A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o

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The probability of missing the first shot is 40%. When she misses the first shot, the probability of missing the second shot is very, very low, only 5%. That means that the probability of missing both shots must be much smaller than the probability of missing the first shot.

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3 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.