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Elza [17]
2 years ago
8

Suppose there are two blocks of solid iron. One block is a cube, three inches on a side. The other block is a cube three miles o

n a side. Obviously, the large cube is many, many times greater volume than the small cube, and many, many times heavier. Is the large cube more dense than the small cube, or less dense?
Mathematics
2 answers:
IrinaK [193]2 years ago
7 0

Answer:

I believe the large cube would be denser.

Step-by-step explanation:

gavmur [86]2 years ago
5 0

Answer:

The density is the same because both cubes are composed of the same element Iron(Fe).

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Step-by-step explanation:

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What is 8 times -8/9
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If cheese is $4.40 per kg, what should I pay for 200 g?
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3 0
3 years ago
I need to know if it’s A B C OR D
Liula [17]

SOLUTION

Consider the property, opposite angle of a cyclic quadrilateral are supplementary

hence

\angle NMP+\angle NOP=180^0

Recall that

\begin{gathered} \angle NMP=\angle M=(8x-24)^0 \\ \text{and } \\ \angle NOP=\angle O=(4x)^0 \end{gathered}

Hnece, we have that

\begin{gathered} \angle M+\angle O=180^0(opposite\text{ angles of a cyclic quadrilateral)} \\ (8x-24)^0+4x^0=180^0 \end{gathered}

Then

\begin{gathered} 8x-24+4x=180 \\ 8x+4x-24=180 \\ 12x-24=180 \\ \text{Add 24 t o both sides } \\ 12x-24+24=180+24 \\ 12x=204 \\ \text{divide both sides by 12} \\ \frac{12x}{12}=\frac{204}{12} \\ \text{Then} \\ x=17 \end{gathered}

Hence

x=17

Since

\begin{gathered} \angle NOP=(4x)^0 \\ \text{substitute the value of x, we have } \\ \angle NOP=4\times17=68^0 \\ \text{Hence } \\ \angle NOP=68^0 \end{gathered}

Therefore

The measure of angle NOP is 68⁰

Answer; 68⁰ (The fourth Option )

5 0
1 year ago
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