What is the solution to the following equation? 3(x-4)-5= x-3

Mathematics

1 answer:

finlep [7]2 years ago

3 0

Answer:

Step-by-step explanation:

$3(x-4)-5=x-3\qquad\text{use the distributive property}\\3x-12-5=x-3\\3x-17=x-3\qquad\text{add 17 to both sides}\\3x-17+17=x-3+17\\3x=x+14\qquad\text{subtract}\ x\ \text{from both sides}\\3x-x=x-x+14\\2x=14\qquad\text{divide both sides by 2}\\\dfrac{2x}{2}=\dfrac{14}{2}\\\\x=7$

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vekshin1

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204,106cm - 2041.06m
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Write a formula for the general term or nth term for the sequence. Then find the indicated term. five halves comma five fourths

nadya68 [22]

Sequence: 5/2, 5/4, 5/8, 5/16
a8=?

a1=5/2
a2=5/4
a3=5/8
a4=5/16

a2/a1=(5/4)/(5/2)=(5/4)*(2/5)=(5*2)/(4*5)=2/4=1/2
a3/a2=(5/8)/(5/4)=(5/8)*(4/5)=(5*4)/(8*5)=4/8=1/2
a4/a3=(5/16)/(5/8)=(5/16)*(8/5)=(5*8)/(16*5)=8/16=1/2
Ratio: r=a2/a1=a3/a2=a4/a3→r=1/2

an=a1*r^(n-1)
a1=5/2, r=1/2
an=(5/2)*(1/2)^(n-1)
an=(5/2)*[1^(n-1)/2^(n-1)]
an=(5/2)*[1/2^(n-1)]
an=(5*1)/[2*2^(n-1)]
an=5/2^(1+n-1)
an=5/2^n

n=8→a8=5/2^8
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Answers:
The formula for the general term or nth term for the sequence is an=5/2^n
a8=5/256

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3 years ago

when you subtract a negative integer from another, will your answer be greater than or less than the integer you started with? e

BlackZzzverrR [31]

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The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$