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vichka [17]
2 years ago
13

Nuts.com sells raw almonds for $10 per pound and roasted pistachios for $12 per pound. Christopher spends $70, before taxes and

shipping, to purchase 6.3 total pounds of nuts. Let a represent the number of pounds of almonds and let p represent the number of pounds of pistachios. Which system of equations represents the situation?
Question 1 options:


{10a+p=70
a+70p=6.3



{10a+12p=70
a+p=6.3



{10a+12p=6.3
a+p=70



{10a+12p=70
10a+12p=6.3
Mathematics
1 answer:
galben [10]2 years ago
3 0

Answer:

second equation

Step-by-step explanation:

10a + 12p = 70  (10 goes with almonds [a], 12 goes with pistachios[p], $10 and $12 is price per pound and $70 is total price, so that's why its = to 70)

a + p = 6.3        (this is total almonds and pistachios adding up to 6.3 pounds)

a = pounds of almonds

p = pounds of pistachios

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Answer:

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12y - 44-3y=26

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now putting the value of  y in 1st equation then

x=3*70/9-11

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now checking this is correct or not in 2nd eqn

4*37/3-3*70/9=26

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Step-by-step explanation:

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3 years ago
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

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sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

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c) Using Heron A² = p(p-a)(p-b)(p-c)

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1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Your question is different from the attachment

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