Tan x /(1 +sec x) + (1+sec x) /tan x
Tan x=sin x / cos x
1+ sec x=1 +1/cos x=(cos x+1)/cos x
Therefore:
tan x /(1 +sec x) =(sin x/cos x)/(cos x+1)/cos x=
=(sin x * cos x) / [cos x* (cos x+1)]=sin x /(Cos x+1)
(1+sec x) /tan x=[(cos x+1)/cos x] / (sin x/cos x)=
=[cos x(cos x+1)]/(sin x *cos x)=(cos x+1)/sin x
tan x /(1 +sec x) + (1+sec x) /tan x=
=sin x /(Cos x+1) + (cos x+1)/sin x=
=(sin²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
Remember: sin²x+cos²x=1⇒ sin²x=1-cos²x
=(1-cos²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
=2 cos x+2 / [sin x(cos x+1)]=
=2(cos x+1) / [sin x(cos x+1)]=
=2 /sin x
Answer : tan x /(1 +sec x) + (1+sec x) /tan x= 2/sin x
Answer:
its choice 1 can i get brainly
Step-by-step explanation:
A number raised to an exponent is the number multiplied by itself the number of times the exponent is.
The exponent is 3, so this means 0.25 is multiplied by itself 3 times.
0.25^3 = 0.25 x 0.25 x 0.25
This is the concept algebra.
Volume of of paint that is required to paint large shipping crate is a liters.
suppose the volume of this crate is x cubic units.
The volume of the next crate to be painted will be 2x cubic units.
Hence the amount of paint required to paint the crate will be:
(volume of bigger crate)/(volume of smaller crate)×(volume of liters required to paint the first crate)
=(2x)/(x)×a
=2a liters
To paint the new crate 2a liters of oil is needed.
Answer:
no, h=7
Step-by-step explanation:
9+9h = 10h+2
9=h+2
7=h
