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2 years ago

Maria says the mean for the following data set is 5. {5, 7, 2, 8, 9, 1, 2, 5}

Mathematics

2 answers:

Vikki [24]2 years ago

7 0

Answer:

4.88

Step-by-step explanation:

I used my calculator to do this;

I did stat and I put in the numbers, I clicked calculate and it said the answer was 4.875. Round that to the nearest hundredth and you'll get 4.88.

ziro4ka [17]2 years ago

6 0

Answer:

4.88

Step-by-step explanation:

The actual mean is 4.88 to the nearest hundredth. She either approximated the sum of elements to 40 instead of 39 or she approximated the actual mean to the nearest whole number.

I think she gave an approximated average or a rounded average, but I am not sure.

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Bárbara corre con rapidez constante de 5 km/h a lo largo de 500 m que separan el colegio de su casa. Demora 3 minutos en recoger

sergiy2304 [10]

Answer:

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2 years ago

Rewrite the equation below so that it does not have fractions.

bearhunter [10]

Answer:

$60+10x=6$

Step-by-step explanation:

Hi there!

$4+\displaystyle \frac{2}{3} x=\frac{2}{5}$

To get rid of the fraction $\displaystyle \frac{2}{3}$ , multiply both sides of the equation by 3 (the denominator):

$3(4+\displaystyle \frac{2}{3} x)=3(\frac{2}{5})\\\\3*4+\frac{3*2}{3}x =\frac{3*2}{5} \\\\12+2x =\frac{6}{5}$

To get rid of the fraction $\displaystyle \frac{6}{5}$ , multiply both sides of the equation by 5 (the denominator):

$\displaystyle 5(12+2x) =5(\frac{6}{5})\\\\5*12+5*2x=\frac{5*6}{5} \\\\60+10x=6$

I hope this helps!

8 0

2 years ago

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Can you help me with this question??

Cloud [144]

Answer:

9.42

Step-by-step explanation:

6 0

2 years ago

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Please answer look at pitot

klio [65]

Answer:

z = 7

Step-by-step explanation:

Based on the midsegment theorem of a triangle, the length of the midsegment of the triangle (z) = ½ of the length of the 3rd side of the triangle (14)

Thus:

z = ½(14)

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4 0

3 years ago

What is the product of (4a+6)(3a-8)

Andreyy89

Answer:

12a²-14a-48

Step-by-step explanation:

4a(3a-8) + 6(3a-8)

= 12a²-32a+18a-48

=12a²-14a-48

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3 years ago