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Juli2301 [7.4K]
3 years ago
15

If you doubled the radius of a sphere, how would the volume change? A. The volume would double. B. The volume would triple. C. T

he volume would quadruple. D. The volume would increase to be eight times that of the original volume.
Mathematics
1 answer:
Ronch [10]3 years ago
7 0
The volume of a sphere, V = (4/3)(PI)(R^3) Let k = (4/3)(PI) Therefore, V = k (R^3) Let R’ = new radius = 2R V’ =k (R’^3) = k (2R)^3 = 8 k R^3 = 8 V The volume would be eight time the original volume.
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Arnold and jamie are both performing the same experiment. Arnold does 20 trials and gets 7 positive results. Jamie does 10 trial
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Answer:

B

Step-by-step explanation:

This is all 1/3 of the number of times the experiment was tried to put in perspective john has 10 apples and he gives 3 away that's about 1/3 of the amount of apples

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How many milliliters are in a gallon?
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3785.41 milliliters per  gallon
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In the order of operations, expressions inside parentheses are evaluated before exponents, True or false?
avanturin [10]

Answer:

The answer is True

Step-by-step explanation:

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3 years ago
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F(0) = -5, f(4) = -3
Karolina [17]

Answer:

y = \frac{1}{2} x - 5

Step-by-step explanation:

Given f(0) = - 5 and f(4) = - 3 , then we have the coordinate points

(0, - 5) and (4, - 3)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, - 5) and (x₂, y₂ ) = (4, - 3)

m = \frac{-3+5}{4-0} = \frac{2}{4} = \frac{1}{2}

The line crosses the y- axis at (0, - 5) ⇒ c = - 5

y = f(x) = \frac{1}{2} x - 5 ← equation of line

4 0
3 years ago
Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 65% chan
amm1812

Answer:

0.49

Step-by-step explanation:

We apply conditional probability to solve this question.

We have Events X and Events Y

P(X) = Probability Christine fails the course = ??? Unknown

P(Y) = Probability Christine finds a tutor

= 0.35

P(Y') = Probability Christine does not find a tutor = 1 - 0.35 = 0.75

P(X|Y) = Decrease in her probability of failing = 0.35

P(X|Y') = Probability that she will fail the course if she does not have a tutor

P(X) = P(X|Y) × P(Y) + P(X|Y') × P(Y')

P(X) = 0.35 × 0.75 + 0.65 × 0.35

P(X) = 0.2625 + 0.2275

P(X) = 0.49

The probability that Christine fails the course is 0.49

8 0
3 years ago
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