1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lubasha [3.4K]
3 years ago
7

What is the value of x?

Mathematics
1 answer:
laiz [17]3 years ago
5 0

yyyyyessssssss oooooo

You might be interested in
Solve a^3 • (-a^2b)^4
Varvara68 [4.7K]

Answer:/?idk

Step-by-step explanation:


8 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
What is -9x - 5 - 8 + x in Simple form
Yanka [14]

Answer:

-10 x-13

Step-by-step explanation:

8 0
3 years ago
Explain how to use a horizontal number line<br> to order four fractions from least to greatest.
horsena [70]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Solution for the above problem: We first find the least common denominator by finding the least common multiple for 4, 3, 2, 6, and 8. We find the LCM by the prime factorization method. Next, place the fractions in order from least to greatest.

4 0
3 years ago
The volume of a metal cylindrical rod is 126 cubic meters. ​The radius is 6 m. ​ ​What is the height of the rod in millimeters?
Dahasolnce [82]

Answer:

1.11 mm

Step-by-step explanation:

The height of a cylinder can be found using the formula: h=V/(πr^2)

This formula was found by taking the formula for the volume of a cylinder and solving for h, or height. Knowing that V is 126 and the radius is 6, we can plug in our known variables in order to solve for h.

8 0
3 years ago
Read 2 more answers
Other questions:
  • I need Help with THIS LIKE...NOWWW!!!!!!
    7·2 answers
  • Help me please<br> Find the surface area of the cylinder. Round your answer to the nearest tenth.
    14·2 answers
  • Find the missing side length.<br> 12<br> 15
    8·2 answers
  • What is 6% of 15? Use a fraction to solve
    5·1 answer
  • Find the measure of arc JM.
    5·1 answer
  • The Venn diagram shows the results of two events resulting from rolling a number cube.
    11·2 answers
  • Helpp plsss I neeed to finish this test ASAP plssssssss thank youu helpp me with this question
    9·1 answer
  • Which equation can be used to prove 1 + tan?(x) = sec2(x)?
    9·1 answer
  • Allison measured a line to be 19.4 inches long. If the actual length of the line is 19.1
    14·1 answer
  • Type the correct answer in the box.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!