I looked it up and this is what it said
Least to greatest: 1.5 qt; 7 c; 64 fl oz
A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
Answer:
3x2-3x+9
Step-by-step explanation:
(h-k)(3)
(X2+1-(x-2))(3)
(x2+1-x+2)(3)
3x2+3-3x+6
3x2-3x+9
