Question

Suppose line n has a slope of 5/7 and passes through (4,8). what is the equation for n in point-slope form?

Answer 1

Answer:

$\large\boxed{y-8=\dfrac{5}{7}(x-4)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have the slope $m=\dfrac{5}{7}$ and the point $(4,\ 8)$.

Substitute:

$y-8=\dfrac{5}{7}(x-4)$