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Anna007 [38]
3 years ago
5

The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 se

nior tickets and 1 child ticket for a total of $38. The school took in $52 on the second day by selling 3 senior citizen tickets and 2 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0
Start by writing out the information you know mathematically (I used S for cost of senior ticket, and C for cost of child ticket. You could use X and Y, or any other combination of letters as variables)

3s + 1c=38
3s + 2c=52

Now, you'll want to eliminate one of the variables by subtracting it out. Remember - Same sign, subtract (and therefore different sign, add).

In this case, 3s exists in the first and second equation, so it's very easy to get rid of. They're both positive, so they have the same sign (+). Same sign, subtract.
3s + 1c=38
-(3s + 2c=52)
__________
0 -1c= -14
-c=-14
C=14

Now, plug c=14 into either of the original equations.

3s + C= 38
3s + 14=38
3s=24
S=8.

So, a child ticket costs $14 and a senior ticket costs $8.
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2 years ago
Write as a single fraction in its simplest form.
yaroslaw [1]

\dfrac{4}{3x-5} + \dfrac{x+2}{x-1}\\\\\\=\dfrac{4(x-1) + (x+2)(3x-5)}{(3x-5)(x-1)}\\\\\\=\dfrac{4x-4 + 3x^2 -5x +6x -10}{(3x-5)(x-1)}\\\\\\=\dfrac{3x^2 +5x-14}{(3x-5)(x-1)}

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2 years ago
Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
Which is a real-world example of two planes intersecting?
leva [86]
The answer to the question above is the third choice, "a shelf on a wall". The shelf is usually made of rectangular pieces of materials that are then connected to each other to form quadrilaterals. The sides of the shelf are planes. 
8 0
2 years ago
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Which of the following numbers is not a perfect square?<br><br> 24<br> 25<br> 64<br> 100
stich3 [128]
Hi! 

A perfect square is the product of when a whole number is multiplied by itself

Ex:

6 × 6 = 36, 36 is the perfect square. 

The number that is being multiplied is the square root. 

So to find the correct answer for this question, let's use the process of elimination. 

100 = 10 × 10 so we can cross out 100

64 = 8 × 8 so we can cross out 64

25 = 5 × 5 so we can cross out 25

Now all we have left is 24, which is not a perfect square. 

Answer: A. 24

Hope this helps :)
8 0
3 years ago
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