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natima [27]
3 years ago
13

Bill spent $42 on fruit at the grocery store. He spent a total of $60 at the store. What percentage of the total did he

Mathematics
2 answers:
svlad2 [7]3 years ago
6 0

Answer:

70%

Step-by-step explanation:

so he spent 42/60

lets simplify by dividing on both sides by 2

21/30

then divide by 3

7/10

which is also 70/100

so 70%

yaaaaayyyy we r done!!!!!!!!!

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

  ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                 PEACE!

Neporo4naja [7]3 years ago
3 0

Answer:

70%

Step-by-step explanation:

To find the total percentage of his $60 dollars that he spent on fruit, we simply take the amount of money spent on fruit divided by the total spent.

% spent on fruit = 42 / 60

% spent on fruit = 0.7

% spent on fruit = 70 %

Cheers.

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Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

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2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

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x=\frac{5}{2}y-\frac{13}{2}  \\

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3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

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\frac{15}{2}y-\frac{39}{2}+4y=15  \\

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\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

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x=\frac{5}{2}\times 3-\frac{13}{2}  \\

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x=\frac{15-13}{2}  \\

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\large\underline{ \underline{ \sf \: x=1 }}

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\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

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Answer:

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