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natta225 [31]
3 years ago
6

a square has 9 inch sides. every side of a pentagon is also 9 inches long. are their perimeters the same? explain

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0
No. A square is four sides, and a pentagon is five sides. The pentagon's perimeter would be greater than the square's because it has more sides.
ivolga24 [154]3 years ago
6 0
No. A square has 4 sides whereas a pentagon has 5 sides. So the pentagon would have more.
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Solve number 8 please
beks73 [17]

Answer:

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k )² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² + y² - 8x + 8y + 23 = 0

collect the x and y terms together and subtract 23 from both sides

x² - 8x + y² + 8y = - 23

using the method of completing the square

add ( half the coefficient of the x / y terms )² to both sides

x² + 2(- 4)x + 16 + y² + 2(4)y + 16 = - 23 + 16 + 16

(x - 4)² + (y + 4)² = 9 ← in standard form

with centre = (4, - 4 ) and r = \sqrt{9} = 3

this is shown in graph b

7 0
2 years ago
Solve the system by substitution<br> -4.5x-2y=-12.5<br> 3.25x-y=-0.75
gogolik [260]

Answer:

The answer to your question is: x = 1, y = 4

Step-by-step explanation:

I'll change decimals to fractions

4.5 = 9/2

12.5 = 25/2

3.25 = 13/4

0.75 = 3/4

                             -9/2 x - 2 y = - 25/2         (I)

                             13/4 x  -   y  = - 3/4            (ll)

Process

               from (II)     y = 13/4x  + 3/4

Sunstitution             -9/2x -2(13/4 x + 3/4) = - 25/2

                               -9/2 x - 13/2 x - 3/2 = -25/2

Multiply by 2         -9 x - 13 x - 3 = -25

                             -22 x = -25  + 3

                            -22 x = -22

                             x = 22/22

                            x = 1

                             y = 13/4 (1) + 3/4

                             y = 16/4

                             y = 4                                          

7 0
3 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
What does the some of triangles always equal?
Mumz [18]

Answer:

the angles always equal 180

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is 5/2 - 1/3 = 1/3y
kati45 [8]

5/2 - 1/3 = 1/3y

I would convert the denominators to 6 to make this easier like this

15/6 - 2/6 = 2/6y

Now you can subtract easily like so

13/6 = 2/6y

Now divide

y = 13/6 divided by 2/6

To divide fractions do keep (numbers) change (sign) and flip (numbers)

y = 13/6 x 6/2

Now multiply:

78/12 = 6 1/2 = 6.5

y = 6.5 is your final answer!

5 0
3 years ago
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