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3 years ago

Does this graph represent a proportional relationship? Explain.

Mathematics

2 answers:

AleksAgata [21]3 years ago

5 0

Answer:

This graph does not represent a proportional relationship because it is not a straight line, and the line does not pass through the origin.

Step-by-step explanation:

Leya [2.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

1. the graph is not consistent with a proportional ration

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Given that ABDC : EFGH, what is m G?<br> 27°<br> 90°<br> 117°<br> 120°

oksian1 [2.3K]

I think it would be 117

Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees

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3 years ago

What are the solutions of x² + 6x - 6 = 10?

Likurg_2 [28]

Answer: x=- 8 or x=2

Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. The quadratic equation is:

$x^{2}+6x-6-10=0\\x^{2}+6x-16=0$

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

$x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}$

$x_1=-8\\x_2=2$

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3 years ago

Read 2 more answers

Which of these WAS NOT one of Huey Long's campaign promises?

kumpel [21]

I think the answer is D.

3 0

3 years ago

A rope is cut into three pieces P, Q, and R the lengths of the pieces are in the ratio 3:5:7 if the rope is 33 feet 9 inches, fi

Olin [163]

P-81
q-135
r-189
find out how many inches the rope is then divide by 15 total parts then multiply each ratio by that

4 0

3 years ago

ANSWER ASAP!!!

denis23 [38]

Answer:

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

Step-by-step explanation:

When an object is moving at a steady speed, we can calculate the time it would take to travel a given distance using the following formula:

$time=\frac{distance}{speed}$ (equation 1)

In this particular, both the given speed and distance are mixed fractions so we'll first convert them into improper fractions to operate more easily:

$speed=10\frac{1}{10} \frac{mi}{h} =\frac{(10*10)+1}{10} \frac{mi}{h}=\frac{101}{10} \frac{mi}{h}$

$distance=4\frac{9}{10}mi=\frac{(4*10)+9}{10}mi=\frac{49}{10}mi$

So, now we can calculate the time using the equation 1:

$time=\frac{distance}{speed}=\frac{\frac{49}{10}mi }{\frac{101}{10} \frac{mi}{h} } =\frac{49*10}{101*10} h$

$time=\frac{49}{101}h=0.49h$

And, if we want the result in minutes:

$time=\frac{49}{101}h*\frac{60min}{1h} =29.11min$

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

5 0

2 years ago