All categories

3 years ago

Does this graph represent a proportional relationship? Explain.

Mathematics

2 answers:

AleksAgata [21]3 years ago

5 0

Answer:

This graph does not represent a proportional relationship because it is not a straight line, and the line does not pass through the origin.

Step-by-step explanation:

Leya [2.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

1. the graph is not consistent with a proportional ration

You might be interested in

You plan to invest $350 in a growth fund that has a rate of 1.5% compounded quarterly. How much money will this investment be wo

nydimaria [60]

Answer:

Hey man I know the answer to this question it would be $449.12

Step-by-step explanation: 350*1.005^50= 449.12

7 0

3 years ago

Read 2 more answers

Number 1d please help me analytical geometry

lesantik [10]

For a) is just the distance formula

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
% (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}$
-----------------------------------------------------------------------------------------
for b) is also the distance formula, just different coordinates and distance

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
% (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}$
--------------------------------------------------------------------------
for c) well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}$

now.. whatever that is, is = BC, so the distance for BC is

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
% (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}$

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d) we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
% (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\
$

$\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}$

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"

7 0

3 years ago

In July 15 days of rain, 10 days without rain, 6 days of only sunshine. What fraction of the days in July did not have any rain?

KonstantinChe [14]

Answer:

16/31 days

Step-by-step explanation:

Add up all the days: 15+10+6=31

Add up the days with no rain: 10+6=16

With no rain as numerator and total as denominator you get an answer of 16/31

5 0

3 years ago

Read 2 more answers

Dean used a triple beam balance to find that the mass of a rock was 40 g and he used a graduate cylinder that measures the volum

zhenek [66]

Answer:

Never bwa hahaha JK try d

Step-by-step explanation:

4 0

3 years ago

Magnetism: So I need help on this question but please explain how you got the answer so I can learn and better provide evidence

kramer

Step-by-step explanation:

A) as you can see there is no current flowing in a bar magnet so (incorrect)

B) Lines of magnetic field is going in A-->B direction so it have starting and ending points.(incorrect)

C) Yes whenever a magnetic object is placed near the another magnetic object they either attract or repell so they have a force in a form of push and pull [correct]

D)No because magnetic field lines goes from North--> South so A is the South pole [ incorrect]

E) Yes it will point always towards North pole of the magnet [correct]

F) yes it depends upon the density of field lines[correct]

G)No the near the magnet is it becomes more stronger as compared to magnet kept far.(incorrect)

So option C E F are correct

Hope this helps

Have a great day

7 0

2 years ago