3 years ago

If the edge lengths of the square were doubled, how would the angle measures be affected?

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

4 angles would be affected

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Paladinen [302]

9514 1404 393

Answer:

3π units

Step-by-step explanation:

The full circumference of a circle with radius 2 is ...

C = 2πr

C = 2π(2) = 4π

The arc shown is 3/4 of the full circle circumference so is ...

3/4C = (3/4)(4π) = 3π . . . units

8 0

3 years ago

Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!

bixtya [17]

Answer:

C {16,29,34}

Step-by-step explanation:

For it to be a right triangle it would have to be {16,30,34}

Hope this helps.

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3 years ago

What is square root of 674

laiz [17]

Answer:

25.9615099715

Step-by-step explanation:

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3 years ago

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Find the surface area of<br> the prism.

tatyana61 [14]

Answer:

Whats the question?

Step-by-step explanation:

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3 years ago

Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your

love history [14]

If we substitute $x=r\cos\theta$ and $y=r\sin\theta$ , we get $r^2=x^2+y^2$ , so that

$z=\cos(x^2+y^2)=\cos(r^2)$

which is independent of $\theta$ , which in turn means the surface can be treated like a surface of revolution.

Consider the function $f(t)=\cos(t^2)$ defined over $0\le t\le1$ . Revolve the curve $C$ described by $f(t)$ about the line $t=0$ . The area of the surface obtained in this way is then

$\displaystyle2\pi\int_C\mathrm dS=2\pi\int_0^1\sqrt{1+f'(t)^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+(-2t\sin(t^2))^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+4t^2\sin^2(t^2)}\,\mathrm dt\approx7.4144$

4 0

3 years ago