Answer:
1.66
Step-by-step explanation:
We need to conduct a chi square test
The statistic used to check this is given by the below
∑(n, 1) = [(O(i) - E(i)] / E(i)
From the question, we're told the observed value is
Freshmen
Sophomore
Junior
Senior.
After that, we then calculate the expected value.
Freshman
0.3 * 300 = $90
Sophomore
0.24 * 300 = $72
Statistics then finally gives us this
X² = (93 - 90²)/90 + (68 - 72)²/72 + (85 - 78)/78 + (64 -60)²/60
X² = 3² / 90 + 4² / 73 + 13² / 78 + 4² / 60
X² = 0.1 + 0.212 + 2.167 + 0.266 x+
X² = 2.745
X = √2.745
X = 1.66
T= F + S .
$6042 = $1780 + S .
S = $6042 - $1780 .
S = $4262
Answer:
The estimated mean number of rockets hits in the region is 533.
Step-by-step explanation:
We are given the following information,
Number of rocket hits | Observed number of regions
0 | 228
1 | 214
2 | 94
3 | 32
4 | 7
5 | 0
6 | 0
7 | 1
We are asked to estimate the mean number of rocket hits in the region.
The mean or expected value is given by
Therefore, the mean number of rockets hits in the region is 533.
Answer:
The third term is -25.
Step-by-step expanation:
d(1)=3
From this equation, we know the first term is 3.
d(n)=d(n−1)−14
This looks like a recursive formula. It is used to find the next term.
n is the variable for the term number that you are solving for.
d(n-1) is the term value before the what you are looking for.
To find the 2nd term, use the formula and substitute values known:
d(n)= d(n−1)−14
d(2) = d(2-1) - 14
d(2) = d(1) - 14
We know d(1)=3
d(2) = 3 - 14
d(2) = -11
Find the third term using the same method:
d(n) = d(n−1)−14
d(3) = d(3−1)−14
d(3) = d(2)−14
d(3) = -11 - 14
d(3) = -25
Answer:
(Choice A)
Juanita gets a strike next game.'
Step-by-step explanation:
Your question is obviously incomplete.
Complete question is:
Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?
(Choice A)
Juanita gets a strike next game.'
(Choice B)
Nina gets a strike next game.
(Choice C)
Neither. Both events are equally likely.
Answer:
Probability of Juanita : P(J)= 24% => 0.24
probability of Nina getting a strike next game: P(N) = 0.17
As you can see 0.24 > 0.17 ----> P(J)>P(N)
Thus it can be concluded that Juanita gets a strike next game is more likely.
so, choice A
