Answer:
C.
Step-by-step explanation:
36 i guess ha please that not right
Those two vehicles are chewing up a lot of ground. Do you drive? I know it's a stupid question. Every American drives, but I have to check. When you see a car coming towards you, does it look like it's going extremely slow, so that 9 could be the answer? Or does it look extremely fast so that 67 could be the answer? I think you should be looking at fast. I live in the country so when something comes towards me I take note of it. So you should be thinking the Impala sees the bug as going north and very fast..
B
Note. The 9 would come up when someone was passing you and they were going 9 mph faster than you were going. If you were going 50 mph and someone passed you at 59 mph. it would appear to you that they were only going 9 mph. Next time you encounter this on the road, see if you agree that that is the way it works.
If A is QIV, then 3π/2 ≤A≤2π;
we have to find out in what quadrant is A/2
(3π/2)/2≤A/2≤(2π)/2 ⇒ 3π/4≤A/2≤π
We can see that A/2 will be in QIII; therefore the sec (A/2) will be negative (-).
1) we have to calculate cos (A/2)
Cos (A/2)=⁺₋√[(1+cos A/2)/2]
We choose this formula: Cos (A/2)= -√[(1+cos A/2)/2], because sec A/2 is in quadrant Q III, and the secant (sec A/2=1/cos A/2) in this quadrant is negative.
Cos (A/2)=-√[(1+cos A)/2]=-√[(1+(1/2)]/2=-√(3/4)=-(√3)/2.
2) we compute the sec (A/2)
Data:
cos (A/2)=-(√3)/2
sec (A/2)=1/cos (A/2)
sec (A/2)=1/(-(√3)/2)=-2/√3=-(2√3)/3
Answer: sec (A/2)=-(2√3)/3
Answer:
66545
Step-by-step explanation:
