Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15
From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,
0.048 is the probability that more than 950 message arrive in one minute.
Answer:
Pretty sure it's B!
Step-by-step explanation:
Over the Y axis- (2,1)
To the left two times= (0,1)
Hope this helped!
First, you would create an equation for this problem.
=
Next, you would cross multiply.
15x = 1,800
Now, you would isolate the x. To do this, you would divide both sides by 15.
x =
120It is a 120% increase. I hope this helps!
Answer:
im really confused soryy that i cant help