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3 years ago

Given that abc=def what is the measure of d

Mathematics

1 answer:

Mazyrski [523]3 years ago

4 0

Answer:

C. 47 deg

Step-by-step explanation:

m<A = 180 - 94 - 39 = 47

m<D = m<A = 47

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a cash register has $1.04 in coins. all the coins are pennies and dimes.there are 24 pennies in the cash register. Which represe

VladimirAG [237]

3-1 finds for she did to is to is to to fix l Fick

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3 years ago

Show work on how you converted them. (also marking brainliest) <3

Dmitry_Shevchenko [17]

Answer:

1. 5700mg

2. 1000cm

3. 0.0453m

4. 37.5 kg/L

Step-by-step explanation:

1. 1gram (g) =1000milligrams(mg)

5.70×1000=5700mg

2. 1 m= 100cm

10×100=1000cm

3. 1000mm=1m

45.3/1000=0.0453m

4. 1000g=1kg

37.5/1000=0.0375

1000ml=1L

1ml= 1/1000= 0.001L

0.0375/0.001= 37.5 kg/L

8 0

3 years ago

Question

mixer [17]

The intervals are given as follows:

In range notation: [-282, 20,320].

In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}

<h3>What is the range of elements notation for interval?</h3>

The range of elements notation for interval is given by:

[a,b].

In which:

a is the smallest value.

b is the greatest value.

In this problem these values are given by:

a = -282, b = 20,320.

Hence the interval in range notation is given by:

[-282, 20,320].

<h3>How to write the interval in set-builder notation?</h3>

The same interval can be written as follows, using set-builder notation?

{x|x ∈ ℝ, a <= x <= b}

Hence, for the situation described in this problem, the set-builder notation for the values is:

{x|x ∈ ℝ, -282 <= x <= 20,320}

More can be learned about notation of intervals at brainly.com/question/27896097

#SPJ1

5 0

2 years ago

What set of reflections would carry hexagon ABCDEF onto itself?

Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

First; we test the given options, until we get the true option

The rule of reflection y =x is:

$(x,y) \to (y,x)$

The rule of reflection across the x-axis is:

$(x,y) \to (x,-y)$

So, we have:

$(y,x) \to (y,-x)$

The rule of reflection y =x is:

$(x,y) \to (y,x)$

So, we have:

$(y,-x) \to (-x,y)$

Lastly, the reflection across the y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$(-x,y) \to (x,y)$

So, the overall transformation is:

$(x,y) \to (x,y)$

Notice that, the original and final coordinates are the same.

This means that:

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself