Answer:
Step-by-step explanation:
In the given triangle
With reference angle A
perpendicular (P) = 3
hypotenuse (h) = 5
So sin A = p/h = 3/5
and
With reference angle C
perpendicular (p)= 4
hypotenuse (h) = 5
Sin C = p/h = 4/5
hope it helps :)
The answer is = -3, hope this helps!
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
A= player A runs batted in
b= player B runs batted in= a-13
250= a + b
substitute b= a-13 for b
250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a
Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b
Hope this helps! :)
Answer:
Children: $13
Adults: $18
Step-by-step explanation:
Well for both sets we can set up the following system of equations,
So first we need to solve for a in the first equation.
3a + 4c = 106
-4c to both sides
3a = -4c + 106
Divide 3 by both sides
<u>a = -4/3c + 35 1/3</u>
Now we plug in that a for a in 2a + 3c = 75.
2(-4/3c + 35 1/3) + 3c = 75
-8/3c + 70 2/3 + 3c = 75
Combine like terms
1/3c + 70 2/3 = 75
-70 2/3 to both sides
1/3c = 4 1/3
Divide 1/3 to both sides
c = 13
Now we can plug in 13 for c in 3a + 4c = 106,
3a + 4(13) = 106
3a + 52 = 106
-52 to both sides
3a = 54
Divide 3 by both sides.
a = 18
<em>Thus,</em>
<em>an adult ticket is $18 and a children's ticket is $13.</em>
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<em>Hope this helps :)</em>