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2 years ago

Compute the requested value. Choose the correct answer.

Mathematics

2 answers:

Fiesta28 [93]2 years ago

7 0

Original price of the item = $14.95

Price after discount = $13.79

Discount offered = original price - price after discount = 14.95- 13.79 = $1.16

Now let us find the percentage of discount offered.

Percentage discount is given by the formula:

$Percentage discount = \frac{MP-SP}{MP}*100$

Where MP= Marked price= original price

SP= selling price= price after discount

$Percentage discount = \frac{1.16}{14.95}*100$

Percentage discount = 7.759 %

Alla [95]2 years ago

7 0

7.759%

$1-\frac{13.79}{14.95}=0.0775919$

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dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

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$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

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Pani-rosa [81]

Answer:

Step-by-step explanation:

we are given a equation of a line

we want to figure out the equation of the perpendicular line passes through the (6,5) points

in order to do so

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we got from our given equation that m=2

because equation of a line is y=mx+b

thus

$\displaystyle m_{ \text{perpendicular}} = - \frac{1}{2}$

remember that, when we want to figure out perpendicular line or parallel line we should the formula given by

$\displaystyle y - y_{1} = m(x - x_{1})$

since we got our perpendicular m is -½, $x_1=6$ and $y_1=5$ , substitute

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$\displaystyle y = - \frac{1}{2} x + 8$

hence,

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2 years ago

Read 2 more answers