Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
Explanation:
Given: Volume of solute = 120 mL
Volume of solvent = 350 mL
Now, total volume of the solution is as follows.
Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.
Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.
Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
Answer:
ClO- = bronsted Lowry base
H2PO4- =Bronsted Lowry base
Explanation:
ClO- = is bronsted Lowry base because it accepts a proton in the reaction
H2PO4- =Bronsted Lowry base because it's a proton donor in the reaction
It is natural and u can't by it
The balanced chemical reaction is expressed as:
<span>8SO2 + 16H2S = 3S8 + 16H2O
We are given the initial amount of the reactants. From there, we determine the limiting reactant. We do as follows:
87.0 g SO2 ( 1 mol / 64.07 g ) = 1.36 mol SO2 ( 16 mol H2S / 8 mol SO2 ) = 2.72 mol H2S
87.0 g H2S ( 1 mol / 34.08 g ) = 2.55 mol H2S ( 8 mol SO2 / 16 mol H2S ) = 1.28 mol SO2
Therefore, the limiting reactant would be H2S. We calculate the maximum amount of S8 that can be produced from the amount of H2S.
2.55 mol H2S ( 3 mol S8 / 16 mol H2S ) ( 256.48 g / 1 mol ) = 122.63 g S8</span>
