What is the maximum mass of s8 that can be produced by combining 87.0 g of each reactant? 8so2+16h2s=3s8+16h20?

1 answer:

6 0

The balanced chemical reaction is expressed as:

<span>8SO2 + 16H2S = 3S8 + 16H2O

We are given the initial amount of the reactants. From there, we determine the limiting reactant. We do as follows:

87.0 g SO2 ( 1 mol / 64.07 g ) = 1.36 mol SO2 ( 16 mol H2S / 8 mol SO2 ) = 2.72 mol H2S
87.0 g H2S ( 1 mol / 34.08 g ) = 2.55 mol H2S ( 8 mol SO2 / 16 mol H2S ) = 1.28 mol SO2

Therefore, the limiting reactant would be H2S. We calculate the maximum amount of S8 that can be produced from the amount of H2S.

2.55 mol H2S ( 3 mol S8 / 16 mol H2S ) ( 256.48 g / 1 mol ) = 122.63 g S8</span>

You might be interested in

Usually hard but brittle<br> Ionic or covalent

aleksandrvk [35]

Answer:

Ionic

Explanation: Ionic compounds tend to be hard and brittle while covalent compounds tend to be softer and more flexible.

Hope this helped!

7 0

3 years ago

Read 2 more answers

What is it called when a gas is converted into a liquid

alex41 [277]

Your answer is probably
Vaporization point

3 0

3 years ago

Read 2 more answers

Sailin' Steve likes to test the buoyancy of different objects. He threw a spherical object into a fluid that has a greater densi

Hunter-Best [27]

The spherical object will float and the square object will sink to the bottom of the fluid as it has greater density. :)

7 0

4 years ago

One of relatively few reactions that takes place directly between two solids at room temperature is In this equation, the in Ba(

yuradex [85]

Answer:

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.

Explanation:

$Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)$

The balance chemical equation is :

$Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)$

Mass of barium hydroxide octahydrate = 6.5 g

Moles of barium hydroxide octahydrate = $\frac{6.5 g}{315 g/mol}=0.020635 mol$

According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:

$\frac{2}{1}\times 0.020635 mol=0.04127 mol$