Precipitation and temperature
Private school and the cashapp one of my favorite classes and I can get it
The amount of energy that was used to heat Cu is 27.6 cal
<u><em>calculation</em></u>
Heat (Q) = M ( mass) x c(specific heat capacity) x ΔT( change in temperature)
where;
Q=?
M = 5.0 g
C=0.092 cal/g°C
ΔT = 80°c-20°c=60°C
Q is therefore = 5.0 g x 0.092 cal / g°c x 60°c =27.6 cal
Answer:
3850g
Explanation:
Solubility is the amount of solute dissolved in a solvent.
Solubility is mass of solute÷mass of solvent
The solvent is 35grams
Solute?
Solubility of solute is 110
110=x/35
= 110 × 35
The amount of residue solute is 3850g
