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3 years ago

12

The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti

on?
OA. It's not moving
OB. It's moving at a constant speed.
OC. It's moving at a constant velocity.
OD
It's speeding up.

1 answer:

marishachu [46]3 years ago

8 0

B because a horizontal line goes straight across which shows a constant rate
Hope this helps!

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I need help with these 4

storchak [24]

Rift Valley Examples

East African
Rhine Rift Valley (Germany)
Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

Bordered by fault zones and separating land masses
A portion of land that drops, forming a valley.
Formed as tectonic plates move.

Fossils - Examples

Bones
Shells
Exoskeletons
Stone imprints of animals.

Non Examples of Fossils

Stones
rocks
Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

5 0

3 years ago

9. How many grams are in 2.0 x 105 molecules of carbon monoxide?

timama [110]

Answer: 9.3 x 10^ 18 g CO

Explanation:

Start by knowing that carbon monoxide is the compound CO. To convert molecules to grams, you first need to convert molecules to moles. This can be done using the conversion factor for Avogadro's Number:

(2.0 x 10^5 molecules CO) x 1 mol CO / 6.02 x 10^23 molecules CO

This cancels molecules CO.

Then, you can convert moles to grams, which is your desired quantity. You can find the number of grams for CO by looking at the periodic table and adding together their masses. C = 12 g and O = 16 g. Total of 28 g CO:

(1 mol CO) x 28 g CO / 1 mol CO

This cancels mol CO, which leaves grams CO.

5 0

3 years ago

How many mL of a 0.375 M solution can be made from 35 g of calcium phosphate?

andrew11 [14]

Answer:

300 mL

Explanation:

the unit formula of calcium phosphate is Ca3(PO4)2

molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol

n = m/M = 35 g/(310 g/mol)

c = n/V

V = n/c = [35 g/(310 g/mol)]/0.375 mol/L

V = 0.30 L = 300 mL

3 0

2 years ago

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in the presence of

In-s [12.5K]

Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

C = 27.6 g

O₂ = 86.5 g remained 12.9 g

O₂ that reacted = 86.5 - 12.9 = 73.6 g

C + O₂ ⇒ CO₂ The equation is balanced

27.6 73.6 ?

MW 12 32 44

Rule of three

12 g of C------------------ 44 g CO2

27.6 g C ------------------ x

x = 27.6(44)/12 = 101.2 g of CO2

32 g of O2 --------------- 44 g of CO2

73.6 g of O2 ------------ x

x = 73.6(44)/32 = 101.2 g of CO2

6 0

3 years ago

Compound X has a molar mass of 416.48 g mol

bazaltina [42]

Answer:

P₂Cl₁₀

Explanation:

From the question given above, the following data were obtained:

Molar mass of compound X = 416.48 g/mol

Percentage of phosphorus (P) = 14.87%

Percentage of Chlorine (Cl) = 85.13%

Molecular formula of X =?

Next, we shall determine the empirical formula of compound X. This can be obtained as follow:

P = 14.87%

Cl = 85.13%

Divide by their molar mass

P = 14.87 / 31 = 0.480

Cl = 85.13 / 35.5 = 2.398

Divide by the smallest

P = 0.480 / 0.480 = 1

Cl = 2.398 / 0.480 = 5

Empirical formula of compound X is PCl₅

Finally, we shall determine the molecular formula of compound X. This can be obtained as follow:

Molar mass of compound X = 416.48 g/mol

Empirical formula = PCl₅

Molecular formula =?

Molecular formula= [Empirical formula]ₙ

[PCl₅]ₙ = 416.48

[31 + (35.5 × 5)]ₙ = 416.48

[31 + 177.5]n = 416.48

208.5n = 416.48

Divide both side by 208.5

n = 416.48 / 208.5

n = 2

Molecular formula = [PCl₅]ₙ

Molecular formula = [PCl₅]₂

Molecular formula = P₂Cl₁₀

Therefore, the molecular formula of compound X is P₂Cl₁₀

4 0

3 years ago