First you rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation
Second you solve it by using the formula of a straight line drawn on Cartesian coordinate system in which “y” is the vet risk axis and “x” the horizontal axis.
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Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
575/100==23/4=5 3/4
hope this helps!
Did you just state the answer? Because it seems like you just answered the question for us.
Answer will be C. 241.6 ft.²
