Complete Question
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Answer:
16.5°
Step-by-step explanation:
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
We solve using Sine rule formula
a/sin A = b/sin B
We are solving for angle W
∠V=136°
Hence:
22 /sin 136 = 9 /sin W
Cross Multiply
22 × sin W = sin 136 × 9
sin W = sin 136 × 9/22
W = arc sin [sin 136 × 9/2.2]
W = 16.50975°
W = 16.5°
A. 1/5k - 2/3j and -2/3j + 1/5k
Step-by-step explanation:
Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.
In
1/5k - 2/3j and -2/3j + 1/5k you notice the operation signs in the terms has been maintained though the position of the terms shifted.
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Equivalent expressions :brainly.com/question/280220
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Answer:
The Ballwin Bears are taller on average, and the Aviston Aces have players whose heights are more consistent.
Step-by-step explanation:
for derby dragon;
mean height = 72 inches
standard deviation = 1.2 inches
for aviston aces:
mean height = 70.8
standard deviation = 0.7 inches
for balwin bears;
mean height = 73 inches
standard deviation = 1.0 inches
the mean height of aviston aces < mean height of derby < mean height of balwin bears
So on average the balwin bears are taller.
The standard deviation of derby dragon is > that of balwin bears > aviston aces.
So the more consistent height is that of aviston aces players.
Answer:
The triangle goes into the square 8 times. Find the area of the triangle and multiply by 8 :) hope this helps, let me know if you need more of an explanation.