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WITCHER [35]
4 years ago
13

Given that R is between S and T, find each missing measure.RS=6, TR=4.5, TS=?

Mathematics
1 answer:
Oksi-84 [34.3K]4 years ago
6 0
4.5+6=10.5
it helps if u draw a line with s,r,t in order
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You plant a rectangular rose garden along the side of your garage. you enclose 3 sides of the garden with 40 feet of fencing. th
ycow [4]
Let x be the length of the garden
and y be the width of the garden.

since you only enclose 3 sides of the garden by a 40 ft fence. so the equation for this is:

2x + y = 40

and the area of the garden is 100 sq ft, so in equation
xy = 100
from equation 1, 2x + y = 40
y = 40 - 2x
substitute to equation 2

xy = 100
x ( 40 - 2x) = 100
40x - 2x^2 = 100
2x^2 - 40x + 100 = 0

x = 2.9 ft
y = 34.5 ft 
5 0
3 years ago
Candlelight Books kept a record of how its sales increased based on
zavuch27 [327]

Answer:

D

Step-by-step explanation:

We need to understand the meaning of slope. The slope means the rate of change of y with every unit change of x.

<em>In our case, it will be rate of change of sales increase (%) with respect to unit change of discount(%).</em>

<em />

The formula for slope is the change in y divided by change in x.

From the 2 points given, we can say that slope is:

\frac{62-32}{20-10}=\frac{30}{10}=\frac{3}{1}

<em>This means "as discount increases 1%, sales increase by 3%". Option D is right.</em>

7 0
3 years ago
Select all operations under which the polynomials 5x - 1 and 3x - 10 are not closed.
sammy [17]
It's division.
Hope I helped!
7 0
3 years ago
Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left
Wewaii [24]
1/5 of 20 is $4. So, 20-4=$16 remaining.
3/8 of 16 is $7.50. So, 16-7.50= $8.50 remaining.
2/7 of 8.5 is $2.43. So, 8.50-2.43 is $6.07

Answer: Ken has $6.07 left after all his purchases.

6 0
4 years ago
Read 2 more answers
What is the solution to the following system?
hodyreva [135]

Answer:

The correct answer is option 3. (20, 4, 5)

Step-by-step explanation:

To solve this problem we use the substitution method.


3x + 10y -12z = 40 (i)


x-5y = 0 (ii)


x - 4z = 0 (iii)  

We start by clearing x in (iii) and clearing y in (ii).


x = 4z (iii)


y = \frac{1}{5}x (ii)


Now we substitute (iii) in (ii)


y = \frac{4}{5}z (iv)


Now we substitute (iii) and (iv) into (i) and clear z.


12z + \frac{40}{5}z -12z = 40 (v)


8z = 40

z = \frac{40}{8}

z = 5

If z = 5 (v)


We substitute (v) in (iii) and then substitute (v) in (iv)


x = 20\\y = 4\\z = 5

The correct answer is option 3.

7 0
3 years ago
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