There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>
1- 5 ways
2- 5/16
3- 1/16
4- 1/16
In the question given above n= 5 p =1/2 q= 1/2 r is the given point.
- <u>Part 1:</u>
The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore
nCr= 5C4= 5 ways
<u>2. Part 2:</u>
The probability that all four people get off the bus on the first stop is given by :
P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16
<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16
<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16
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I believe the appropriate volume is 160.
Answer:
no mode , 6 , 6.24
Step-by-step explanation:
Answer:
6.67 m/s
Step-by-step explanation:
This system has no solution.
x = -7y + 24 can be rewritten as x = 24 - 7y
to simplify x + 7y = 32, we have to subtract 7y from both sides
x = 32 - 7y
Now, our system is as follows:
x = 24 - 7y
x = 32 - 7y
