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3 years ago

eden caught 14 fish and then ate some. write an expression to represent the number of fish eden has left.

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

5 0

Answer:

14 - A = L

Step-by-step explanation:

A = The number of fish Eden ate

L = The number of fishes left

=> 14 - A = L

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(8x-16)/x^2-13x+22 simpifyed completly

Veronika [31]

Answer:

3. 8 over x minus 11 , x ≠ 11

Step-by-step explanation:

(8x-16)/(x²-13x+22) =
8(x-2)/(x² - 2x - 11x + 22) =
8(x - 2)/(x - 2)(x - 11) =
8/(x - 11)

6 0

3 years ago

In a recent semester at a local university, 490 students enrolled in both General Chemistry and Calculus I. Of these students, 6

posledela

I think its 149/ 490. Not sure, but pretty confident. Hope this helps.

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3 years ago

A company manufactures tires at a cost of $40 each. The following are probabilities of defective tires in a given production run

asambeis [7]

Answer:

The expected cost of the company for a 3000 tires batch is $120255

Step-by-step explanation:

Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.

Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are $A_1,\dots, A_n$ events that partition the whole sample space, and we have a random variable X over the sample space, then

$E(X) = p(A_1)E(X|A_1) + \dots + p(A_n)E(X|A_n)$ .

So, in this case, we have the following

$E(X) = P(p=0\%)E(X|p=0\%)+P(p=1\%)E(X|p=1\%)+P(p=2\%)E(X|p=2\%)+P(p=3\%)E(X|p=3\%) = 0.1\cdot 3000\cdot 0 + 0.3\cdot 3000\cdot 0.01+ 0.4\cdot 3000\cdot 0.02+ 0.2\cdot 3000\cdot 0.03 = 51$ .

Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.

Finally, note that the cost of the batch would be 40Y+45X. Then

$E(40Y+45X) = 40E(Y)+45E(X) = 40\cdot 2949+45\cdot 51=120255$

3 0

4 years ago

I need the answer to this please.

ohaa [14]

Answer:

Step-by-step explanation:

Its (1,3) and (-3, -2)

6 0

3 years ago

Find the 11th term of the geometric sequence 10, 20, 40, ...10,20,40,

elena-14-01-66 [18.8K]

11th term is 10240

Step-by-step explanation:

Step 1: Given the sequence 10,20,40. So a(1) = 10, common ration, r = 20/10 = 2 Find the 11th term using the nth term formula, a(n) = ar^n-1

⇒ a(11) = 10 × 2^10 = 10 × 1024 = 10240

8 0

3 years ago