Answer:
A. 121 ⇒ III. 11
B. 64 ⇒ II. 4 and IV. 8
C. 27 ⇒ I. 3
D. 125 ⇒ V. 5
E. 16 ⇒ II. 4
Step-by-step explanation:
Let us find the correct answer
∵ 121 = 11 × 11
∴ The square root 121 is 11
∴ A. 121 ⇒ III. 11
∵ 64 = 8 × 8
∴ The square root of 64 is 8
∵ 64 = 4 × 4 × 4
∴ The cube root of 64 is 4
∴ B. 64 ⇒ II. 4 and IV. 8
∵ 27 = 3 × 3 × 3
∴ The cube root of 27 is 3
∴ C. 27 ⇒ I. 3
∵ 125 = 5 × 5 × 5
∴ The cube root of 125 is 5
∴ D. 125 ⇒ V. 5
∵ 16 = 4 × 4
∴ The square root of 16 is 4
∴ E. 16 ⇒ II. 4
Answer:
They must buy 501 pounds of produce for the membership to be worth it.
Step-by-step explanation:
You can solve this question by first finding the difference between $0.10 and $0.25.
With some simple subtraction (0.25-0.10) we can find that the difference is that a non-membership person would pay $0.15 per pound.
You then divide 75 by 0.15 to find the extra weight it would take for the produce to equal $75. You should get 500 pounds.
At 500 pounds, the price would be equal if you had a membership or not.
You then must add 1 pound to make it more favorable to have the membership.
At 501 pounds the person with the membership would pay $125.10 and the person without the membership would pay $125.25
The original expression is equal to 0 because anything multiplied by 0 is equal to 0. Solve inside the brackets for the possible answer choices to find what will equal 0.
Start with the first expression. Add 4 and negative 4 will become 0, and -1 times 0 is equal to 0. Let's solve for the others just to be sure.
In the second expression, solving inside the brackets gives you 8. -1 times 8 is equal to -8.
Adding 4 and negative 4 in the third expression leaves you with 0. But, 1 + 0 is equal to 1.
Adding negative 4 and negative 4 gives you the answer of -8, and -1 times -8 is equal to 8.
Your answer is the first expression, or A.
Answer:
a) P = 5000(1.014)^y
b) 5,908
Step-by-step explanation:
Here, we want to write an exponential growth model;
a)The model will be represented as;
P = 5000( 1.014)^y
where P is the population at a particular year after 2010
y is the number of years after 2010
b.) For 2022;
y = 2022-2010 = 12
P = 5000(1.014)^12
P = 5,908 approximately
