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3 years ago

Help i need the answer idk what or how to do this

Mathematics

1 answer:

natta225 [31]3 years ago

6 0

14^(7x) = 17^(-8-x)

Take the log of both sides:

7x*log 14 = -(8+x)*log 17, or 7x^log 14 = -8*log 17 - x*log 17.

Grouping the x terms, we get x(7*log 14 + log 17)= -8*log 17

Then:
-8*log 17
x= -------------------------- (answer)
7*log 14 + log 17

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Given:

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$\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2$

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Subtract 100 from both sides.

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Taking square root on both sides.

$4\sqrt{14}=\text{opposite}$

Using trigonometric ratio formula:

$$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}$

$$\sin\theta =\frac{4\sqrt{14} }{18}$

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$$\csc\theta =\frac{18}{4\sqrt{14} }$

$$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}$

$$\cos \theta=\frac{10}{18}$

$$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}$

$$\sec \theta=\frac{18 }{10}$

$$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}$

$$\tan \theta=\frac{4\sqrt{14} }{10}$

$$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}$

$$\cot \theta=\frac{10}{4\sqrt{14} }$

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