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3 years ago

Explain why precise knowledge of the stimulus is critical in a task estimating auditory sensitivity.

Biology

1 answer:

sergeinik [125]3 years ago

5 0

Answer:

The physical stimulus is the only part of the test that is measureable, and therefore, knowable. The stimulus is our anchor for our estimate of the listener's perception.

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Describe the role of Cyanobacteria in charging Earth's early atmosphere

kvv77 [185]

Cyanobacteria were very simple organisms and performed were an role in changing Earth's early atmosphere. They carried out photosynthesis to produce the materials they needed to grow. In this process, they release Oxygen which is needed to sustain life on Earth for Humans and other organisms.

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3 years ago

PLZ HELP!!!!!!!!!!!!!!! DUE TODAY!!!!!

inessss [21]

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3 years ago

Is the creation of genetically unique offspring by two parents?

viktelen [127]

The answer is sexual reproduction in which the creation of offspring by fertilization consisting 2 haploid gametes come together to form a diploid zygote with a new genetic combination. The main difference between sexual and asexual reproduction is that asexual reproduction results in a genetically identical offspring whereas sexual reproduction results in a unique offspring in which offspring with a new genetic combination.

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3 years ago

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m

Vanyuwa [196]

This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
$v=\frac{2\pi{r}}{T}$
 $=\frac{2\pi{r}}{1.88*365.25*86400}$ m/s, accounting for leap years
$=3.371*10^{-8}\pi{r}$ m/s

The centripetal force, Fc, generated is
$Fc=\frac{mv^2}{r}$
where m=mass of mars = 6.39*10^(24) kg
$=\frac{mv^2}{r}$
$=\frac{6.39*10^{24}v^2}{r}$
$=7.26168*10^9\pi^2r$

The gravitation pull from the sun, Fg, is given by
$Fg=\frac{GMm}{r^2}$
where G=grav. const., =6.67408*10^(-11) m^3 kg^(-1) s^(-2)
M=mass of sun=1.989*10^(30) kg
$=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}$
$=\frac{8.4826*10^44}{r^2}$

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
$7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}$
Solving for the real root:
$r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}$
$=\frac{1.1681263*10^{35}}{\pi^2}$
=2.279*10^11 m

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3 years ago

What is the name of the type of puller that uses a heavy weight that is slid against its handle?

svlad2 [7]

A slide hammer puller. A slide hammer puller can be used to pulll a bearing from a bored hole that is pressed into. They are adjustable with either a collet or puller jaws. To remove the bearing, slide the weight back hard until it hits the flat area on the rear of the puller.

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3 years ago

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