The properties are the commutative, associative, additive identity and distributive properties
You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²) b = 9.16
With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
Senior tickets (x)
Child tickets (y)
First day: 3x + 5y = 70
second day: 12x + 12y = 216
Solve the system of equations (use elimination)
Multiply first equation by -4 -4(3x + 5y = 70), which makes it
-12x - 20y = -280
(+)12x + 12y = 216 add to second equation
-8y = -64
divide by -8. y = 8
Plugin the y value to either equation ( I will choose first equation)
3x + 5(8) =70
3x+ 40 = 70
3x = 30
x = 10
Senior tickets are $10, child tickets are $8
Answer:
x=64
Step-by-step explanation: because the sides are both the same so do 128/2 which equals 64 so x=64
Answer:
The amount he needs to pay = $ 650
Step-by-step explanation:
Area= h* (a+b/2)
= 10 * (10+16/2)
= 10 * (26/2)
= 10 * 13 = 130 sq.feet
The amount he needs to pay = 130 * 5 = $ 650
