There are 36 drama DVD's
<em><u>Solution:</u></em>
Given that there are 48 DVD's of comedies and dramas on shelf
25 % of DVD's are comedies
To find: number of drama DVD's
Total number of dvd = 48
Number of comedy dvd = 25 % of 48
Let us find 25 % of 48
![\rightarrow 25 \% \text{ of } 48\\\\\rightarrow 25 \% \times 48\\\\\rightarrow \frac{25}{100} \times 48\\\\\rightarrow 0.25 \times 48 = 12](https://tex.z-dn.net/?f=%5Crightarrow%2025%20%5C%25%20%5Ctext%7B%20of%20%7D%2048%5C%5C%5C%5C%5Crightarrow%2025%20%5C%25%20%5Ctimes%2048%5C%5C%5C%5C%5Crightarrow%20%5Cfrac%7B25%7D%7B100%7D%20%5Ctimes%2048%5C%5C%5C%5C%5Crightarrow%200.25%20%5Ctimes%2048%20%3D%2012)
Thus, number of comedy dvd = 12
Thus we get,
number of drama DVD's = Total number of dvd - number of comedy dvd
number of drama dvd = 48 - 12 = 36
Thus there are 36 drama dvd's
The answer is “x=y+2” hopefully this helps :)))))
Answer: 200+40x=600
Step-by-step explanation:
200+40x=600
600-200=400
40x=400
40/40= 1 or x
400/ 40=10
x=10
Negative, because Correlation and slope have the same direction (Sxy will be negative)
Answer:
the Larger poster is 9ft long by 6ft wide
Step-by-step explanation:
In order to find the length and width values of the large poster we first need to find the width of the smaller poster since we are already given the length. Since we are also provided with the perimeter we can add the length twice and subtract it from the perimeter which would give us the value of both width sides of the rectangle, then we simply divide by 2 to get the value of the individual width.
10ft = 3ft + 3ft + w + w
10ft = 6ft + 2w
4ft = 2w
2ft = w
Since the larger poster is 3 times as big for the length and the width we simply multiply the smaller poster's length and width by 3...
L = 3 * 3 = 9ft
W = 2 * 3 = 6ft
Finally, we can see that the Larger poster is 9ft long by 6ft wide