Answer:
to enjoy it to the fullest because God put us here for a purpose
Explanation:
Answer:
The percentage for the homozygous dominant trait would be 25%. in the F2 generation.
Explanation:
Suppose true-breeding parents with the different alleles for the same trait are TT (dominant) and tt (recessive) than the cross of these parents will produce gametes T, T and t, t respectively.
These gametes will form offspring ultimately. Produced offspring will be TT (homozygous dominant), Tt (heterozygous dominant), Tt (heterozygous dominant) and tt (homozygous recessive).
Thus, the percentage of dominant homozygous phenotype in F2 would be 25% in respect of the dominant allele which is TT.
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Answer:
NADH - ID; ATP - CS; Citrate - CS
Explanation:
The citric acid cycle also called the tricarboxylic acid cycle (TCA) or Kreb’s cycle is a catabolic pathway for aerobic organisms. In the cycle, acetyl-coA is metabolized in a series of steps.
The regulation of the cycle is done by the availability of substrates produced within the cycle. It is known as feedback inhibition.
Succinyl-CoA – High concentration of succinyl-CoA inhibits a-ketoglutarate dehydrogenase.
Citrate – CS. Citrate synthase catalyses the combination of acety-CoA with oxaloacetic acid to form citrate. High concentration of citrate inhibits it.
NADH – For isocitrate to be converted to oxalosuccinate, it needs to bind with NAD+. ID catalyses the reaction. NADH inhibits ID by displacing NAD+
ATP Enzymes – CS. ATP inhibits citrate synthase through allosteric inhibition. As more ATP is produces, citrate synthase becomes less saturated with acetyl-CoA, therefore there is less acetyl-Co A to form citrate.