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3 years ago

What is the graph of y = |x - 2|?

Mathematics

1 answer:

Margaret [11]3 years ago

6 0

Answer:

Step-by-step explanation:

Graphing y = (x - h)2 + k

In the graph of y = x2, the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point.

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To increase an amount by 17.5% what single multiplier would you use?

zaharov [31]

You would multiply that number by 1.175

Remember that 17.5%=17.5/100=0.175

I this case, there is a whole number that is increasing by 17.5% so we add a whole to the 17.5%

100%+17.5%=117.5% or 1.175

So if 'x' was the number, the expression would look like:

1.175x

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3 years ago

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Janice makes 4 pizzas for dinner. There are 5 people to eat dinner. How much will each person get to eat?

TEA [102]

Hello!

Divide the number of pizzas Janice makes by the number of people who will eat dinner.

4 ÷ 5 = 0.8

Each person will get to eat 0.8 of the pizza.

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3 years ago

Lilly bought stock at $83.60. The next day, the price increased by $15.35. Then this price changed by $-2.15.Wgat was the final

rodikova [14]

The final stock price would be $96.8

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3 years ago

Need help with this math

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3 years ago

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Given: AB || DE , AD bisects BE. Prove: ABC = DEC using the ASA postulate.

Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

$\triangle ABC$ and $\triangle DEC$ .

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then alternate angles are equal.

i.e. AB || ED and $\angle B$ and $\angle E$ are alternate angles $\Rightarrow$ $\angle B = \angle E$ .

2. When two lines are cutting each other, angles formed at the crossing of two, are known as Vertically opposite angles and they are are equal.

$\Rightarrow \angle ACB = \angle DCE$

Also, it is given that AD bisects BE.

i.e. EC = CB

1. $\angle B = \angle E$

2. EC = CB

3. $\angle ACB = \angle DCE$

So, we can in see that in $\triangle ABC$ and $\triangle DEC$ , two angles are equal and side between them is also equal to each other.

Hence, proved that $\triangle ABC$ $\cong$ $\triangle DEC$ .

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3 years ago