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Stella [2.4K]
3 years ago
13

15(x-3) over 5 = 3(2x-3) What is X?

Mathematics
2 answers:
fgiga [73]3 years ago
5 0

Answer:

x=0

Step-by-step explanation:

SCORPION-xisa [38]3 years ago
4 0

Answer: x= infinite solutions

there are infinite solutions and when graphing it shows you that they are together they are infinte solutions

Step-by-step explanation:

15(x-3)/5=3(2x-3)

15(x-3)/5=6x-9

*5             *5

15(x-3)=30x-45

15x-45=30x-45

-15x      -15x

-45=15x-45+45

+45

0=15x

0/15=x

0=x

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What is the absolute value of 2 1/2<br><br> Write your answer as a mixed number.
Greeley [361]

Answer:

it is 2 1/2

Step-by-step explanation:

I hope this helps

6 0
3 years ago
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
three baskets contain 8, 8 and 11 soaps. can the soaps be rearranged so that there is an equal whole number of soaps in each bas
Doss [256]
Yes because 8+8+11=27 and 27÷3=9
6 0
3 years ago
a baseball and a bat cost $1.10 and if this bat costs .10 cents more than the ball. how much did the ball cost?
kari74 [83]
<u>Define x:</u>
Let the cost of the ball be x.
Ball = x
Bat = x + 0.1

<u>The total cost is $1.10:</u>
x + x + 0.1 = 1.1
2x + 0.1 = 1.1
2x = 1
x = 0.5

<u>Find the cost of the bat and the ball:</u>
ball = x = $0.50
bat = x + 0.1 = 0.5 + 0.1 = $0.60

Answer: The ball cost $0.50


8 0
3 years ago
Please explain and/or show your work!! :)
PolarNik [594]
\left[ \begin{matrix} 2 & a \\ -1 & -2 \end{matrix} \right] + \left[ \begin{matrix} b & 4 \\ -2 & 1 \end{matrix} \right]

This addition of matrices can be combined into one matrix.
To add matrices, add the corresponding components of each matrix.

After adding, we'll have the following

\left[ \begin{matrix} 2+b & a+4 \\ -3 & -1 \end{matrix} \right]

This matrix should be equal to the matrix on the right-hand side of the equation. This means that each corresponding component of this matrix and the other matrix should be equivalent.

This means that

2+b=1
AND
a+4=0

Solving these one-step equations will give the values of a = -4 and b = -1. That's answer choice D.
3 0
3 years ago
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