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oksano4ka [1.4K]
3 years ago
12

A rectangular playground has a perimeter of 180 feet. If the width of the playground is 24 feet less than the length,what is the

width,in feet,of the playground? Show work.

Mathematics
2 answers:
Serjik [45]3 years ago
8 0

Answer:

lenght=57

width=33

Step-by-step explanation:

The perimeter of a rectangle is calculated using the formula

P=2(w+l) where P is the perimeter, w is the width and l is the length.

We know

P=180

lenght (l) = x (unknown value)

width (w)= x-24

Now we change these values in the formula

180=2((x-24)+x)

180=2(x-24+x)

180=2(2x-24)

180=4x-48

180+48=4x

228=4x

x=228/4

x=57

Therefore

P=180

w= x-24 =57-24 <em>=33</em>

<em>l=57</em>

To confirm:

P=2(w+l)=2(33+57)=2(90)=180

I hope you find this information useful and interesting! Good luck!

denis-greek [22]3 years ago
3 0
I hope this helps you

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Answer:

C = 5

Step-by-step explanation:

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8 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
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Find B  C.

3 0
3 years ago
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