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insens350 [35]
3 years ago
12

John collected 17 leaves to feed his caterpillar collection if he wanted to split the leaves equally amongst the four cages how

much should he put in each cage how much should he put in each cage between what two numbers does your answer lie
Mathematics
2 answers:
natita [175]3 years ago
8 0
Since 17/4= 4.25. He would put 4 leaves in each cage. And just drop the remaining amount
Papessa [141]3 years ago
3 0

Answer:

It lies between the numbers 4 and 5

Step-by-step explanation:

If John has 17 leaves and 4 cages then he should put 17/4, or 16/4+1/4 which is 4+0.25, or 4.25 in each cage.

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Step-by-step explanation:

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3 years ago
a truck driver needs to drive his load to a destination that is 2760 miles away how many miles on average will he have to drive
vladimir1956 [14]
1 week = 7 days....so 1 week and 1/2 day = 7.5 days

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6 0
3 years ago
Suppose you buy a $50 coffee maker in an area where the sales tax is 8%. When you check out, 8% of $50 would be added to your to
ASHA 777 [7]

Answer:

4

Step-by-step explanation:

8% is also 8/100. This would be true for all percents 0 to 100%. If it were 42% it can be written as 42/100.

So, 8% is 8/100. If you want to find 8/100 of 50 multiply them.

8/100 * 50/1 = (8*50) /100

400/100 = 4

7 0
3 years ago
Read 2 more answers
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
2. Write the following expanded form: 3.26x10^(-2). *
Aleksandr [31]

Answer:

o.o326

Step-by-step explanation:

when dealing with negative exponents you move the decimal to the left

8 0
3 years ago
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