First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
3
The x-intercept of the graph is -4
Graph B
The last graphing question is kinda hard to read so. It should not be c or d. Look for the graph where the line passes through the y-axis starts 30.
Step-by-step explanation:
Answer:
5 5/7
Step-by-step explanation:
-4•6/7•-5/3
Put the numbers as fractions
-4/1•6/7•-5/3
Rewriting
-4/1 * 6/3 * -5/7
Simplifying the middle fraction
-4/1 * 2/1 * -5/7
Multiply the first two terms
-8/1 * -5/7
Multiplying
40/7
Changing from an improper fraction to a mixed number
7 goes into 40 5 times with 5 left over
5 5/7
Answer:
£140 increased by 5% is £147.00
You can divide the fractions
