3 years ago

Write the equation of the line that contains the point (2,1) and is parallel to the line 4x−2y=3

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

8 0

Answer:

y=2x-3

Step-by-step explanation:

4x-2y=3

-2y=3-4x

2y=4x-3

y=4x/2-3/2

y=2x-1.5 m1=2 (the number near x)

If the searched line is parallel to the line 4x−2y=3, m1=m2= 2

y=m2x+b - the searched line

1=2*2+b

b=-3

y=2x-3

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If f(x) = 2x - 4 and g(x) = x^2+3, find each value.<br><br> 19. (f - g)(x)<br> 20. (f • g)(x)

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$(f - g)(x) = f(x) - g(x) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2x - 4) - ( {x}^{2} + 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x - 4 - {x}^{2} - 3 \\ \red{ \boxed{\therefore (f - g)(x) = - {x}^{2} + 2x - 7}}$