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xz_007 [3.2K]
3 years ago
13

Please help me with this question

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

e=\frac{T- n}{T+n}

<u>Step-by-step explanation:</u>

Here we have , to make e as subject of formula and given expression is:

T = \frac{n(1+e)}{(1-e)}

⇒ T = \frac{n(1+e)}{(1-e)}

⇒ T(1-e) = \frac{n(1+e)}{(1-e)}(1-e)

⇒ T(1-e) = n(1+e)

⇒ T-T(e)= n+n(e)

⇒ T-T(e)+T(e)= n+n(e)+T(e)

⇒ T= n+e(T+n)

⇒ T- n=e(T+n)

⇒ e=\frac{T- n}{T+n}

Therefore, e=\frac{T- n}{T+n} .

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The required inverse function  f^{-1}(x) = (2x - 3 ) / 4.

Given that,
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To find  f^{-1}(x)

<h3>What are functions?</h3>

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Let f(x) = y
y = (2x + 3) / 2
y * 2 = 2x + 3
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x = (2y - 3) / 2
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Add 1 to both sides:

\sqrt{x+3} = x+1

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

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Under this assumption, we square both sides and we have

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