All categories

3 years ago

Please help me with this question

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

4 0

$e=\frac{T- n}{T+n}$

Step-by-step explanation:

Here we have , to make e as subject of formula and given expression is:

$T = \frac{n(1+e)}{(1-e)}$

⇒ $T = \frac{n(1+e)}{(1-e)}$

⇒ $T(1-e) = \frac{n(1+e)}{(1-e)}(1-e)$

⇒ $T(1-e) = n(1+e)$

⇒ $T-T(e)= n+n(e)$

⇒ $T-T(e)+T(e)= n+n(e)+T(e)$

⇒ $T= n+e(T+n)$

⇒ $T- n=e(T+n)$

⇒ $e=\frac{T- n}{T+n}$

Therefore, $e=\frac{T- n}{T+n}$ .

You might be interested in

Two parallel lines are intersected by a transversal. Prove: Angle bisectors of the same side interior angles are perpendicular.

n200080 [17]

Answer:

The answer is given below

Step-by-step explanation:

From the diagram below,Let the line AB and CD be parallel line. Let transversal line EF cut AB at Y and transversal line EF cut CD at Z.

The bisector of ∠BYZ and ∠DZY meet at O. Therefore ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2

∠BYZ and ∠DZY are interior angles.

∠BYZ + ∠DZY = 180 (sum of consecutive interior angles)

∠BYZ/2 + ∠DZY/2 = 180/2

∠BYZ/2 + ∠DZY/2 = 90°

In ΔOYZ:

∠YZO + ∠ZYO + ∠YOZ = 180 (sum of angles on a straight line).

But ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2

∠DZY/2 + ∠BYZ/2 + ∠YOZ = 180

90 + ∠YOZ = 180

∠YOZ = 180 - 90

∠YOZ = 90°

Therefore Angle bisectors of the same side interior angles are perpendicular.

3 0

3 years ago

Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2

lbvjy [14]

Step 1:
Start by putting $\frac{d}{dx}$ in front of each term

$\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]$
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
$\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]$
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
$\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
$(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}
$
$y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make $\frac{dy}{dx}$ the subject
$-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
$cos(x) \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)$
$[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)$
$\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y}$ ⇒ Final Answer

5 0

4 years ago

A meteorologist reports that the ration of snowfall in January to total snowfall during the average winter is 2 to 5. If 34 inch

Zepler [3.9K]

Answer:

13.6 inches.

Step-by-step explanation:

First do 2/5 = x/34, then multiply 34 by 2 and you get 68, then 68 divided by 5 is 13.6!

Hope this helped!

4 0

3 years ago

5+b=25 there were boxes that had this = + =25 =

balandron [24]

The answer for 5+b=25 isb=20

4 0

3 years ago

Read 2 more answers

⦁ Find the length of the third angle of a triangle given that the first two angles are 35 and 70. Show your work.

UNO [17]

180 - 70 = 110
110 - 35 = 75
The third angle is 75

3 0

3 years ago